![\"c\u00e1ch](\"\/wp-content\/uploads\/2024\/09\/cach-danh-lo-de-chinh-xac.png\")
Tuy nhi\u00ean c\u00f3 m\u1ed9t \u0111i\u1ec1u m\u00e0 anh em ch\u01b0a bi\u1ebft \u0111\u00f3 l\u00e0 d\u00e0n n\u00e0y c\u0169ng kh\u00e1 \u0111a d\u1ea1ng. Trong series ng\u00e0y h\u00f4m nay, Ch\u00fang t\u00f4i <\/strong>s\u1ebd gi\u1edbi thi\u1ec7u v\u1edbi anh em c\u00e1ch b\u1eaft c\u1ea7u \u0111\u1ec1 n\u00e0y v\u00e0 chi\u1ebfn thu\u1eadt ch\u01a1i \u0103n ti\u1ec1n t\u1eeb nh\u00e0 c\u00e1i.<\/p>\n D\u00e0n \u0111\u1ec1 36 s\u1ed1<\/strong> l\u00e0 kh\u00e1i ni\u1ec7m v\u1ec1 c\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 m\u00e0 anh em c\u1ea7n l\u00e1p d\u1ee5ng nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p kh\u00e1c nhau \u0111\u1ec3 t\u1eeb \u0111\u00f3 l\u1ef1a ch\u1ecdn ra m\u1ed9t b\u1ed9 khung g\u1ed3m 36 con \u0111\u1ec1 \u0111\u1eb9p nh\u1ea5t trong t\u1ed5 h\u1ee3p t\u1eeb 00 \u2013 99 \u0111\u1ec3 ch\u01a1i trong ng\u00e0y h\u00f4m nay.<\/p>\n Nh\u00ecn chung th\u00ec d\u1ea1ng \u0111\u1ec1 36 s\u1ed1 n\u00e0y hi\u1ec7n nay \u0111ang \u0111\u01b0\u1ee3c \u01b0a chu\u1ed9ng b\u1edfi s\u1ed1 qu\u00e2n v\u1eeba ph\u1ea3i, \u00edt t\u1ed1n ngu\u1ed3n v\u1ed1n \u0111\u1ea7u t\u01b0, d\u1ec5 b\u1eaft v\u00e0 t\u1ed1n \u00edt th\u1eddi gian soi c\u1ea7u.<\/p>\n Kh\u00e1i ni\u1ec7m.<\/p>\n<\/div>\n \u0110\u1eb7c bi\u1ec7t \u0111\u00e2y l\u00e0 m\u1ed9t trong nh\u1eefng c\u00e1ch \u0111\u00e1nh \u0111\u1ec1 hi\u1ec7u qu\u1ea3 b\u1eadc nh\u1ea5t \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng cho c\u1ea3 3 mi\u1ec1n B\u1eafc, Trung, Nam. Ch\u00ednh v\u00ec \u0103n quanh n\u0103m, li\u00ean t\u1ee5c n\u00ean c\u00e1c con s\u1ed1 n\u00e0y \u0111\u01b0\u1ee3c cho l\u00e0 b\u1ea5t b\u1ea1i v\u00e0 \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng qua r\u1ea5t nhi\u1ec1u th\u1ebf h\u1ec7 \u0111\u1ebfn ng\u00e0y nay.<\/p>\n Ngo\u00e0i nh\u1eefng l\u1ee3i th\u1ebf th\u00ec d\u00e0n \u0111\u00e1nh \u0111\u1ec1 36 qu\u00e2n c\u0169ng c\u00f3 h\u1ea1n ch\u1ebf nh\u1ea5t \u0111\u1ecbnh. \u0110\u00f3 l\u00e0 ch\u00fang ta l\u00e3i \u00edt h\u01a1n so v\u1edbi \u0111\u00e1nh d\u00e0n \u00edt s\u1ed1 hay b\u1ea1ch th\u1ee7. Tuy nhi\u00ean h\u1ea1n ch\u1ebf n\u00e0y kh\u00f4ng \u0111\u00e1ng k\u1ec3 n\u1ebfu nh\u01b0 c\u00f3 \u0111\u01b0\u1ee3c chi\u1ebfn thu\u1eadt ch\u01a1i hi\u1ec7u qu\u1ea3.<\/p>\n 36 qu\u00e2n trong d\u00e0n \u0111\u1ec1 kh\u00f4ng \u0111\u01a1n gi\u1ea3n l\u00e0 c\u1ed1 \u0111\u1ecbnh nh\u01b0 nhi\u1ec1u anh em v\u1eabn l\u1ea7m t\u01b0\u1edfng. T\u1eeb nhi\u1ec1u c\u00e1ch b\u1eaft kh\u00e1c nhau ch\u00fang ta c\u0169ng c\u00f3 nh\u1eefng d\u00e0n 36 r\u1ea5t ri\u00eang bi\u1ec7t. D\u00f9 v\u1eady th\u00ec d\u01b0\u1edbi \u0111\u00e2y l\u00e0 t\u1ed5ng h\u1ee3p nh\u1eefng d\u00e0n \u0111\u1ec1 36 qu\u00e2n b\u1ea5t b\u1ea1i \u0111\u01b0\u1ee3c c\u00e1c cao th\u1ee7 s\u1ed1 h\u1ecdc ho\u00e0n thi\u1ec7n qua nhi\u1ec1u th\u1ebf h\u1ec7.<\/p>\n D\u1ea1ng d\u00e0n n\u00e0y r\u1ea5t d\u1ec5 b\u1eaft. Ch\u00fang ta ch\u1ec9 c\u1ea7n d\u1ef1a v\u00e0o v\u00e0o c\u00e1c \u0111\u1ea7u \u0111\u00edt c\u1ee7a c\u00e1c c\u1eb7p s\u1ed1 theo quy lu\u1eadt nh\u01b0:<\/p>\n \u0110\u1ec3 c\u00f3 \u0111\u01b0\u1ee3c 36 s\u1ed1 th\u00ec ch\u00fang ta c\u1ea7n s\u1eed d\u1ee5ng 2 ch\u1ea1m \u0111\u1ec1. Anh em c\u00f3 th\u1ec3 t\u1ef1 t\u1ea1o d\u00e0n \u0111\u1ec1 d\u1ea1ng n\u00e0y b\u1eb1ng c\u00e1ch l\u1ea5y 2 ch\u1ea1m k\u1ebft nh\u1ea5t \u0111\u1ec3 ch\u01a1i. C\u00e1ch b\u1eaft c\u0169ng r\u1ea5t \u0111a d\u1ea1ng nh\u01b0: \u0111\u00e1nh b\u1ec7t ch\u1ea1m \u0111\u1ec1, \u0111\u00e1nh c\u00e1c ch\u1ea1m ch\u01b0a n\u1ed5 trong tu\u1ea7n, \u0111\u00e1nh c\u00e1c ch\u1ea1m \u0111\u1ec1 theo b\u1ea1c nh\u1edb\u2026<\/p>\n V\u00ed d\u1ee5:<\/strong><\/span> Ch\u1ea1m 1, 7 s\u1ebd t\u1ea1o ra d\u00e0n s\u1ed1 01, 07, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 21, 27, 31, 37, 41, 47, 51, 57, 61, 67, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 81, 87, 91, 97<\/span>. T\u01b0\u01a1ng t\u1ef1 c\u00f3 th\u1ec3 t\u1ea1o ra c\u00e1c d\u00e0n 36 theo c\u00e1c ch\u1ea1m kh\u00e1c nhau.<\/p>\n Hi\u1ec7n nay c\u00f3 r\u1ea5t nhi\u1ec1u anh em \u0111\u00e3 th\u00e0nh c\u00f4ng v\u1edbi d\u00e0n \u0111\u1ec1 theo c\u00e1c \u0111\u1ea7u \u0111u\u00f4i b\u1ecf k\u00e9p. \u0110\u1ec3 t\u1ea1o \u0111\u01b0\u1ee3c d\u00e0n n\u00e0y ch\u00fang ta c\u1ea7n \u0111\u1ebfn 4 \u0111\u1ea7u ho\u1eb7c 4 \u0111u\u00f4i. Sau khi soi c\u1ea7u \u0111\u1ea7u \u0111u\u00f4i k\u1ebft ch\u00fang ta s\u1ebd s\u1eed d\u1ee5ng c\u00e1c c\u00f4ng c\u1ee5 l\u00ean d\u00e0n v\u00e0 lo\u1ea1i \u0111i to\u00e0n b\u1ed9 c\u00e1c c\u1eb7p k\u00e9p b\u1eb1ng.<\/p>\n V\u00ed d\u1ee5<\/strong><\/span>: D\u00e0n 36 con t\u1eeb \u0111\u1ea7u 1, 2, 3, 4 s\u1ebd l\u00e0 10, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 45, 46, 47, 48, 49<\/span>.<\/p>\n Ch\u01a1i d\u00e0n \u0111\u1ec1 36 qu\u00e2n mu\u1ed1n b\u1ea5t b\u1ea1i c\u0169ng c\u1ea7n nh\u1eefng chi\u1ebfn thu\u1eadt chu\u1ea9n x\u00e1c. Hi\u1ec7n t\u1ea1i cho hi\u1ec7u q\u1ee7a nh\u1ea5t ch\u00ednh l\u00e0 \u0111\u1ea7u t\u01b0 nu\u00f4i khung v\u1edbi c\u00e1c t\u1eadp khung c\u01a1 b\u1ea3n s\u1ebd l\u00e0 3 ng\u00e0y, 5 ng\u00e0y.<\/p>\n D\u01b0\u1edbi \u0111\u00e2y s\u1ebd l\u00e0 b\u1ea3ng t\u00ednh ti\u1ec1n c\u1ee5 th\u1ec3 cho t\u1eebng khung m\u00e0 ch\u1eafc ch\u1eafn anh em s\u1ebd c\u1ea7n \u0111\u1ec3 qu\u1ea3n l\u00fd ngu\u1ed3n v\u1ed1n t\u1ed1t h\u01a1n.<\/p>\n Ch\u00fang ta s\u1ebd \u0111\u00e1nh theo t\u1ef7 l\u1ec7 1:2:4 v\u1edbi t\u1ef7 l\u1ec7 tr\u1ea3 th\u01b0\u1edfng 1 \u0103n 99.<\/p>\n => Ng\u00e0y 1:<\/strong> \u0110\u00e1nh 10k\/s\u1ed1.<\/p>\n T\u1ed5ng \u0111\u00e1nh: 10 x 36 = 360k.<\/p>\n Th\u1eafng: 10 x 99 = 990k.<\/p>\n L\u00e3i ng\u00e0y 1: 990 \u2013 360 = 630k. Ng\u00e0y 1 ch\u01b0a v\u1ec1 th\u00ec \u0111\u00e1nh ti\u1ebfp ng\u00e0y 2.<\/p>\n => Ng\u00e0y 2:<\/strong> \u0110\u00e1nh 20k\/s\u1ed1.<\/p>\n T\u1ed5ng \u0111\u00e1nh 2 ng\u00e0y: 360 + (20 x36) = 1.080k.<\/p>\n Th\u1eafng: 20 x 99 = 1.980k.<\/p>\n L\u00e3i: 1.980 \u2013 1.080 = 900k. Ng\u00e0y 2 ch\u01b0a v\u1ec1 th\u00ec \u0111\u00e1nh ng\u00e0y 3.<\/p>\n => Ng\u00e0y 3:<\/strong> \u0110\u00e1nh 40k\/ s\u1ed1.<\/p>\n T\u1ed5ng \u0111\u00e1nh 3 ng\u00e0y: 1.080 + (40 x 36) = 2.520k.<\/p>\n Th\u1eafng: 40 x 99 = 3.960k.<\/p>\n L\u00e3i: 3.960 \u2013 2.520 = 1.440k.<\/p>\n<\/span>\u0110\u1ecbnh ngh\u0129a d\u00e0n \u0111\u1ec1 36 s\u1ed1 l\u00e0 g\u00ec?<\/h2>\n
<\/p>\n
<\/span>D\u00e0n \u0111\u1ec1 36 s\u1ed1 g\u1ed3m nh\u1eefng con g\u00ec?<\/h2>\n
<\/span>a) D\u00e0n \u0111\u1ec1 36 con c\u1ed5 \u0111i\u1ec3n<\/h3>\n
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<\/span>b) D\u00e0n \u0111\u1eb7c bi\u1ec7t 36 s\u1ed1 theo ch\u1ea1m<\/h3>\n
<\/p>\n
<\/span>c) D\u00e0n \u0111\u1eb7c bi\u1ec7t 36 qu\u00e2n theo \u0111\u1ea7u \u0111u\u00f4i (b\u1ecf k\u00e9p)<\/h3>\n
<\/span>C\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 36 s\u1ed1 khung 3 ng\u00e0y, 5 ng\u00e0y b\u1ea5t b\u1ea1i<\/h2>\n
<\/span>D\u00e0n 36 qu\u00e2n khung max 3 ng\u00e0y v\u00e0 c\u00e1ch v\u00e0o ti\u1ec1n<\/h3>\n
<\/p>\n
Chi ti\u1ebft b\u1ea3ng v\u00e0o ti\u1ec1n 3 ng\u00e0y v\u00e0 k\u1ebft qu\u1ea3 th\u1ef1c t\u1ebf<\/strong><\/h4>\n